A 50 kg sled is sliding freely on a flat surface- Its velocity varies with time according to vt-3t-9msFind the magnitude of the frictional force that brings the sled to rest-

The correct option is A 150 N The velocity of sled #160; #160; #160; #160; #160; v(t) = 3t + 9 #160; m/s Thus its acceleratio ...

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Standard XII

Physics

Applications of Radius of Curvature

A 50 kg sle...

Question

A $50 k g$ sled is sliding freely on a flat surface. Its velocity varies with time according to
$v (t) = - 3 t + 9 \frac{m}{s}$
Find the magnitude of the frictional force that brings the sled to rest.

150 N

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350 N

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500 N

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675 N

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900 N

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Solution

The correct option is A $150 N$
The velocity of sled $v (t) = - 3 t + 9$ $m / s$
Thus its acceleration $a = \frac{d v (t)}{d t} = - 3 + 0 = - 3$ $m / s^{2}$
Magnitude of frictional force required $| f | = m | a | = 50 \times 3 = 150$ N

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A 50kg sled is sliding freely on a flat surface. Its velocity varies with time according to v(t)=−3t+9msFind the magnitude of the frictional force that brings the sled to rest.

The correct option is A 150NThe velocity of sled v(t)=−3t+9 m/sThus its acceleration a=dv(t)dt=−3+0=−3 m/s2Magnitude of frictional force required |f|=m|a|=50×3=150 N

A $50 k g$ sled is sliding freely on a flat surface. Its velocity varies with time according to
$v (t) = - 3 t + 9 \frac{m}{s}$
Find the magnitude of the frictional force that brings the sled to rest.

The correct option is A $150 N$
The velocity of sled $v (t) = - 3 t + 9$ $m / s$
Thus its acceleration $a = \frac{d v (t)}{d t} = - 3 + 0 = - 3$ $m / s^{2}$
Magnitude of frictional force required $| f | = m | a | = 50 \times 3 = 150$ N