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Werner's Coordination Theory

A 50 ml 1.92 ...

Question

A 50 ml 1.92% (w/v) solution of a metal ion $M^{n +}$ (atomic weight = 120) was treated with $6 g$ hydrazinehydrate (80% pure) and mixture was saturated with $C O_{2}$ gas when entire metal gets precipitated as a complex $[M (H_{2} N - N H C O O)_{n}]$ . The complex was filtered off and the filtrate was titrated with $0.3 M K I O_{3}$ in the presence of conc. $H C l$ according to the following equation:
$N_{2} H_{4} + I O_{3}^{-} + 2 H^{+} + 2 C l^{-} \to I C l + 3 H_{2} O + N_{2} ↑$
The volume of $\frac{M}{10} K I O_{3}$ solution needed for the end point to arrive was $160 ml$ . Find the value of $n$ .

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Solution

$n_{M}^{n +} = \frac{1.92}{120} mol = 0.016 mol$
$n_{hydrazinehydrate} = \frac{0.8 \times 6}{50} mol = 0.096 mol$
$n_{e q K I O_{3}} = 4 \times 0.3 \times 0.160 L = 0.192 n_{e q h y d r a z i n e h y d r a t e} reacted with K I O_{3}$
$∴ n_{hydrazinehydrate} left after reaction with M^{n +} = \frac{0.192}{4} mol = 0.048 mol$
$∴ n_{hydrazinehydrate} reacted with M^{n +} = (0.096 - 0.048) mol = 0.048 mol$
$\frac{n_{M^{+}}}{n_{hydrazinehydrate}} = \frac{1}{n} = \frac{0.016}{0.048} = 3$

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Similar questions

50 m L

1.92 %

w / v

solution of a metal ion

M^{n +} a t . w t = 60

was treated with

5.32 g

hydrazinehydrate

(N_{2} H_{4} . H_{2} O) 90 % p u r e

and the mixture was saturated with

C O_{2}

gas when entire metal gets pecipitated as a complex

[M (N H_{2} - N H C O O)_{n}]

the complex was filtered of and the filterate was titrated with

M / 10 K I O_{3}

in the presence of

c o n c . H C l

according to the following equation :

N_{2} H_{4} + I O_{3}^{-} + 2 H^{+} + C l^{-} \to I C l + 3 H_{2} O + N_{2} ↑

M / 10 K I O_{3}

solution needed for end point to arrive was

480 m L

. Find the value of

n

.

1.5

g sample containing oxalic acid and some inert impurity was dissolved in enough water and volume was made up to

250

20

mL portion of this solution was then mixed with

30

mL of an alkali solution. The resulting solution was then treated with stoichiometric amount of

C a C l_{2}

just needed for precipitation of oxalate as

C a C_{2} O_{4}

solution was filtered off and filtrate was finally titrated against

0.1 M H C l

8.0

mL of acid was required to reach the equivalence point. At last the above neutral solution was treated with excess of

A g N O_{3}

A g C l

obtained was washed, dried and weighed to be

0.4305

g. Determine the mass percentage of oxalic acid in the original sample.

Q. A definite amount of

B a {C l}_{2}

was dissolved in

H C l

solution of unknown normality,

20

mL of this solution was treated with

21.4

\frac{N}{10} N a O H

for complete neutralization. Further

20

mL of solution was added to

50

\frac{N}{10} {N a}_{2} C O_{3}

and the precipitate was filtered off. The filtrate reacted with

10.5

0.08 N H_{2} S O_{4}

using phenolphthalein as an indicator. The strength of

H C l

(g/L) in the mixture is (as nearest integer) :

Q. A definite amount of

B a C l_{2}

was dissolved in

H C l

solution of unknown normality.

20

mL of this solution was treated with

21.4

0.1 N N a O H

for complete neutralization. Further

20

mL of the solution was added to

50

0.1 N

N a_{2} C O_{3}

and the precipitate was filtered off. The filtrate reacted with

10.5

0.08 N

H_{2} S O_{4}

using phenolphthalein as indicator. The strength of

B a C l_{2}

in mixture is :

1

g of a moist sample of a mixture of

K C l O_{3}

K C l

was dissolved in water and made upto

250

25

mL of this solution was treated with

S O_{2}

to reduce chlorate into chloride and the excess

S O_{2}

was boiled off. When the total chloride was precipitated,

0.1435

g of AgCI was obtained. In another experiment,

25

mL of the original solution was treated with

30

0.2

F e S O_{4}

F e S O_{4}

37.5

0.08

N solution of an oxidizing agent for complete oxidation. The molar ratio of chlorate and chloride in the given mixture

F e^{2 +}

C I O_{3}^{-}

according to equation,

C l O_{3}^{-} + 6 F e^{2 +} + 6 H^{+} \to C I^{-} + 6 F e^{3 +} + 3 H_{2} O

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