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Common Ion Effect

A 50 mL solut...

Question

A 50 mL solution of strong acid of pH = 1 is mixed with a 50 mL solution of strong acid of pH = 2. The pH of the mixture will be :
$(l o g_{10} 5.5 = 0.74)$

A

0.74

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B

1.26

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C

1.76

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D

1.5

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Solution

The correct option is B 1.26
$p H_{a c i d 1} = 1; M_{1} = [H^{+}] = 10^{- 1} p H_{a c i d 2} = 2; M_{2} = [H^{+}] = 10^{- 2} M_{3} = [H^{+}]_{m i x t u r e} V_{1} = 50 m L, V_{2} = 50 m L V_{3} = V_{1} + V_{2} = 100 m L A p p l y i n g :$
$M_{1} V_{1} + M_{2} V_{2} = M_{3} V_{3} M_{3} = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{3}} = \frac{(10^{- 1} \times 50) + (10^{- 2} \times 50)}{100} M_{3} = [H^{+}] = 5.5 \times 10^{- 2} p H = - l o g_{10} [H^{+}] = - l o g_{10} (5.5 \times 10^{- 2}) p H = - (0.74 - 2) = 1.26 A n s$

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Common Ion Effect

Standard XII Chemistry

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