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Question

A 50 cm string fixed at both ends produces resonant frequency 384 Hz and 288 Hz without there being any other resonant frequency between the two. Find the speed of the wave on the string in cm/sec.

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Solution

Given :
f1=384 Hz
f2=288 Hz
l=50 cm
change in a frequency, Δf=f1f2
Δf=384288=96 Hz
The fundamental frequency is f0=96 Hz
λ=2l=2×0.50=1 m
wave speed of the string will be
v=f0λ=96×1=96 m/s
v=9600 cm/sec

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