A 50cm string fixed at both ends produces resonant frequency 384Hz and 288Hz without there being any other resonant frequency between the two. Find the speed of the wave on the string in cm/sec.
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Solution
Given : f1=384Hz f2=288Hz l=50cm change in a frequency, Δf=f1−f2 Δf=384−288=96Hz The fundamental frequency is f0=96Hz λ=2l=2×0.50=1m wave speed of the string will be v=f0λ=96×1=96m/s v=9600cm/sec