Question

A 50 turn closely wound circular coil of radius 12 cm carries a current of 2.4 A, the field at center of coil is.

• A. $6.3\times {10}^{-3}Tesla$
• B. $4.8\times {10}^{-4}Tesla$
• C. $2.4\times {10}^{-4}Tesla$
• D. $6.3\times {10}^{-4}Tesla$

Answer 1

The correct option is D $6.3\times {10}^{-4}Tesla$

$B=\frac{{\mu }_{0}Ni}{2r}=\frac{4\pi \times {10}^{-7}\times 50\times 2.4}{2\times 12\times {10}^{-2}}$
$=\frac{2\pi \times {10}^{-7}\times 50\times 2.4}{2.4\times {10}^{-1}}=200\pi \times {10}^{-6}$
$=2\pi \times {10}^{-4}$ Tesla
$=6.3\times {10}^{-4}$