A 500g ball is thrown vertically upwards with a kinetic energy 58.8J. At what height KE is reduced to half the KE at the point of projection?
A
2m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is B6m Given: The ball is thrown upwards with K.E=58.82J and hence at this height change in kinetic energy = change in potential energy or 58.8=mgh But after a particular height the K.E becomes half of its original value and thus: 58.82/2=mgh or in other words at h=6m the K.E becomes half of the original value.