A $500 g m$ gun fires a $2 g m$ bullet with a muzzle velocity of $1600 m s^{- 1}$ . The velocity of the gun is:

- 0.64 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 6.4 m s^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6.4 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.64 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $- 6.4 m s^{- 1}$
Given , mass of gun $m_{g} = 500 g m = 0.5 k g$
mass of bullet $m_{b} = 2 g m = 0.002 k g$
final velocity of bullet $v_{b} = 1600 m s^{-} 1$

Let $v_{g}$ be the final velocity of gun
Since, the gun and bullet are initially at rest, their initial velocities are $u_{b} = u_{g} = 0$ .

Using linear momentum conservation:
$m_{b} u_{b} + m_{g} u_{g} = m_{b} v_{b} + m_{g} v_{g}$

$0 = 0.002 \times 1600 + 0.5 \times v_{g}$

$\Rightarrow v_{g} = - 6.4 m / s$

Suggest Corrections

Similar questions

10

1

5 m / s

^{- 1}

^{- 1}

A gun weighing 4 kg fires a bullet of 40 g with a velocity of $500 m s^{-} 1$ . With what velocity does the gun recoil?

10 g

1 k g

5 m / s

4 k g

40 g

500 m s^{- 1}

Join BYJU'S Learning Program