A 500 Hz modulating voltage fed into an FM generator produces a frequency deviation of 2.25 kHz. If amplitude of the voltage is kept constant but frequency is raised to 6 kHz then the new deviation will be

4.5 kHz

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54 kHz

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27 kHz

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15 kHz

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Solution

The correct option is B 54 kHz
$m_{f}$ = $\frac{δ}{f_{m}} = \frac{2250}{500}$ = 4.5
$∴$ New deviation = 2( $m_{f} f_{m}$ ) = 2 $\times$ 4.5 $\times$ 6 = 54 kHz.

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A 500 Hz modulating voltage fed into an FM generator produces a frequency deviation of 2.25 kHz. If amplitude of the voltage is kept constant but frequency is raised to 6 kHz then the new deviation will be

The correct option is B 54 kHzmf = δfm=2250500 = 4.5 ∴ New deviation = 2(mffm) = 2 × 4.5 × 6 = 54 kHz.

The correct option is B 54 kHz
$m_{f}$ = $\frac{δ}{f_{m}} = \frac{2250}{500}$ = 4.5
$∴$ New deviation = 2( $m_{f} f_{m}$ ) = 2 $\times$ 4.5 $\times$ 6 = 54 kHz.