Question

A 500 kg horse pulls a cart of mass 1500 kg along a level horizontal road with an acceleration of $1m/s^2$. If the coefficient of sliding friction between the cart and ground is 0.2, then the force exerted by the horse on the cart in forward direction is: Assume limiting friction is acting)

• A. $3000N$
• B. $4500N$
• C. $5000N$
• D. $6000N$

Answer 1

Answer: (B)

$4500N$

Given,

Mass of cart, $m=1500kg$

Acceleration, $a=1m/s^2$

So, force acting on the cart $=m\times a=1500N$

Normal reaction, $N=1500\times 10=15000N$

Friction force $=\mu N$

Coefficient of friction, $\mu =0.2$

So, frictional force $=0.2\times 15000=3000N$

Hence, the force exerted by the horse $=3000+1500=4500N$