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Question

A 500μF capacitor is charged at a steady rate of 100μC/sec. The potential difference across the capacitor will be 10V after an interval of-

A
5 sec
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B
20 sec
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C
25 sec
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D
50 sec
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Solution

The correct option is D 50 sec
Given,
Capacitance, C=500μF
Potential difference, V=10V
Rate of charging, q=100μC/sec
=100×106C/sec
To fine, t=?
We know that,
Q=qt
t=Qq=5×103C100×106C×sec=50sec
It will take 50sec to raise the potential difference .
Hence,
Option D is correct.

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