A $500 g m$ ball moving at $15 m / s$ slows down uniformly until it stops. If the ball travels $15 m$ , what was the average net force applied while it was coming to a stop?

Open in App

Solution

mass of the ball m =500g =0.5kg
velocity of the ball V = 15m $s^{- 1}$
distance travelled =s =15m
from $v^{2} - u^{2} = 2 a s ⟹ v^{2} = u^{2} + 2 a s$
0= $15^{2}$ +2a(15)
-225=30a $⟹$ a= -7.5m $s^{- 2}$
net force applie F=M $\times a$
F=0.5 $\times (- 7.5)$
= -3.75N
this force 3.75 N has to be applied in the opposite direction

Suggest Corrections

Similar questions

Man A takes 5 seconds to stop a 1 kg ball thrown at 10 m/s at him. Man B takes the same time to return the same ball coming at him at 5 m/s exactly in the opposite direction with same speed. Who applied more force?

Q. A cricketer stops a ball travelling at the speed of

10 m/s

0.5 s

. If the mass of the ball is

0.1 kg

then the average force applied by the player is

Q. A player stops a football weighing

0.5 k g

which comes flying towards him with a velocity of

10 m / s

. If the impact lasts for

\frac{1}{50} t h

sec and the ball bounces back with a velocity of

15 m / s

, then the average force involved is :

a body is moving with a velocity of 15m/s and it comes to rest in 20m/s, what was the acceleration

Q. A car moving at 40 km/hr is to be stopped by applying brakes in the next 4 m. If the car weighs 2000 kg, what average force must be applied to stop it?

Join BYJU'S Learning Program

A 500gm ball moving at 15m/s slows down uniformly until it stops. If the ball travels 15m, what was the average net force applied while it was coming to a stop?

mass of the ball m =500g =0.5kgvelocity of the ball V = 15ms−1distance travelled =s =15mfrom v2−u2=2as⟹v2=u2+2as0=152 +2a(15)-225=30a ⟹ a= -7.5ms−2net force applie F=M×a F=0.5 ×(−7.5) = -3.75N this force 3.75 N has to be applied in the opposite direction

A $500 g m$ ball moving at $15 m / s$ slows down uniformly until it stops. If the ball travels $15 m$ , what was the average net force applied while it was coming to a stop?