A $50 m l$ after-shave lotion at $30$ % alcohol is mixed with $30 m l$ of pure water. What is the percentage of alcohol in the new solution?

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Solution

Given:
$v_{1} = 50 m l$
Percentage alcohol $= 30$ % , $v_{2} = 30 m l$
Percentage alcohol $= \frac{V of alcohol}{v_{1}} \times 100$
Volume of alcohol $= \frac{50}{100} \times 30 = 15 m l$
Now, $v_{2}$ is added, Total volume $v = v_{1} + v_{2} = 80 m l$
Volume of alcohol remains same
Percentage of alcohol $= \frac{V of alcohol}{v_{1}} \times 100 = \frac{15}{80} \times 100$
Hence percentage of alcohol is $= 18.75$ %

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A 50ml after-shave lotion at 30% alcohol is mixed with 30ml of pure water. What is the percentage of alcohol in the new solution?

Given: v1=50mlPercentage alcohol =30% , v2=30ml Percentage alcohol =V of alcoholv1×100Volume of alcohol =50100×30=15ml Now, v2 is added, Total volume v=v1+v2=80mlVolume of alcohol remains same Percentage of alcohol=V of alcohol v1×100=1580×100Hence percentage of alcohol is =18.75%

A $50 m l$ after-shave lotion at $30$ % alcohol is mixed with $30 m l$ of pure water. What is the percentage of alcohol in the new solution?