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Question

A 5.2 molal aqueous solution of methyl alcohol (CH3OH) is supplied. What is the mole fraction of methyl alcohol in the solution?


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Solution

Step 1: Given data

The concentration of an aqueous solution of methyl alcohol =5.2mol

Step2: Calculating mole fraction

A 5.2 molal aqueous solution of methyl alcohol indicates that 5.2 moles of methyl alcohol are present in one kilogram (or 1000g) of water.

The molecular weight of water=18g

Moles of water=givenweightofwatermolecularmassofwater

=1000g18gmol-155.56mol

Mole fraction of methyl alcohol=molesofmethylalcoholmolesofmethylalcohol+molesofwater

=5.2mol55.56mol+5.2mol0.086

Therefore, the mole fraction of methyl alcohol in the solution is 0.086


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