Question

A $5cm$ long solenoid having $10$ ohm resistance and $5mH$ inductance is joined to a $10V$ battery. At steady state, the current through the solenoid (in ampere) will be

• A. $5$
• B. $2$
• C. $1$
• D. zero

Answer 1

The correct option is C $1$

At steady state inductor behave like short circuit.

$i=\frac{v}{r}=\frac{10}{10}=1A$