CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
61
You visited us 61 times! Enjoying our articles? Unlock Full Access!
Question

A 5gm lump of clay, moving with a velocity of 10 cm/s towards east, collides head-on with another 2 gm lump of clay moving with 15 cm/s towards west. After collision, the two lumps stick together. The velocity of the compound lump will be-

A
5 cm/s towards east
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5 cm/s towards west
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.88 cm/s towards east
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2.5 cm/s towards west
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2.88 cm/s towards east

Given that,

m1=5g

m2=2g

v1=10cm/s

v2=15m/s

Now, according to the law of conservation

m1v1+m2v2=(m1+m2)v

5×102×15=7v

v=207

v=2.88cm/s

Hence, the velocity is 2.88 cm/s in east


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
A Sticky Situation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon