A 5m long aluminium wire (Y=7×10^{10} N/m^{-2} )of diameter 3mm supports a 40Kg mass in order to have the same elongation in the copper wire (Y=12×10^{10} N/m^{-2}) of the same length under the same weight the diameter should now be (in mm)

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Q. A 5 m long aluminium wire

(Y = 7 \times 10^{10} N / m^{2})

of diameter 3 mm supports a 40 kg mass. In order to have the same elongation in a copper wire

(Y = 12 \times 10^{10} N / m^{2})

of the same length under the same weight, the diameter should now be, in mm

Q. A 5 m long aluminium wire

(Y = 7 \times 10^{10} N / m^{2})

of diameter 3 mm supports a 40 kg mass. In order to have the same elongation in a copper wire

(Y = 12 \times 10^{10} N / m^{2})

of the same length under the same weight, the diameter should now be, in mm

A $5$ m long aluminium wire $(Y = 7 \times 10^{10} N m^{- 2})$ of diameter $3$ mm supports a $40$ kg mass. In order to have the same elongation in the copper wire $(Y = 12 \times 10^{10} N m^{- 2})$ of the same length under the same weight, the diameter of the copper wire should now be (in mm).

Q. A copper wire and a steel wire of the same diameter and length 1 m and 2 m respectively are connected end and a force is applied which stretches their combined length by 1 cm. How much each wire is elongated respectively. Y of copper =

1.2 \times 10^{10}

M m^{- 2}

and Y of steel +

2.0 \times 10^{10} N m^{- 2}

Q. A copper wire of length

2.4 m

and a steel wire of length

1.6 m

, both the diameter

3 m m

, are connected end to end. The ratio fo elongation of steel to the copper wires is then

(Y_{c o p p e r} = 1.2 \times 10^{11} N m^{- 2}, Y_{s t e e l} = 2 \times 10^{11} N m^{- 2})

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