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Electric Potential at a Point in Space Due to a Point Charge Q

A = 6.2m, 2m,...

Question

$A = (6.2 m, 2 m), B = (6 m, 5 m)$

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Solution

Here the x-component of electric field is given only so $E_{x} = 20 N / C, E_{y} = 0, E_{z} = 0$
Thus, $E_{x} = - \frac{d V}{d x}$
or $\int_{A}^{B} d V = - \int_{4}^{6} E_{x} d x$ (as $x$ varies from $x = 6.2 m$ to $x = 6 m$ )
or $V_{B} - V_{A} = - 20 (6 - 6.2) = 4 V$

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