A 6 feet tall man sees an apple on the ground, $6 \sqrt{3}$ feet away from him. What is the angle of depression (in degrees) when he is looking at the apple?

60

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Solution

The correct option is A 60

$In triangle ABC, B C = 6 f e e t, A C = 6 \sqrt{3} f e e t .$
$The angle of depression will be ∠ A B C .$

From the figure, we know that,
$t a n B = \frac{A C}{B C} \Rightarrow t a n B = \frac{6 \sqrt{3}}{6} = \sqrt{3} \Rightarrow B = 60 ° .$

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A 6 feet tall man sees an apple on the ground, 6√3 feet away from him. What is the angle of depression (in degrees) when he is looking at the apple? 60

The correct option is A 60 In triangle ABC, BC=6feet,AC=6√3feet. The angle of depression will be ∠ABC. From the figure, we know that, tan B=ACBC⇒tan B=6√36=√3⇒B=60°.

A 6 feet tall man sees an apple on the ground, $6 \sqrt{3}$ feet away from him. What is the angle of depression (in degrees) when he is looking at the apple?

60

The correct option is A 60

$In triangle ABC, B C = 6 f e e t, A C = 6 \sqrt{3} f e e t .$
$The angle of depression will be ∠ A B C .$

From the figure, we know that,
$t a n B = \frac{A C}{B C} \Rightarrow t a n B = \frac{6 \sqrt{3}}{6} = \sqrt{3} \Rightarrow B = 60 ° .$