A $6 %$ glucose solution and $2 %$ solution of ‘x’ show same relative lowering of vapour pressure, assuming ‘x’ to ba a non-electrolyte, the molecular weight of ‘x’ is

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Solution

The correct option is C 60
$\frac{w_{1}}{M_{1}} = \frac{w_{2}}{M_{2}} \frac{6}{180} = \frac{2}{M_{2}} M_{2} = 60$

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A 6% glucose solution and 2% solution of ‘x’ show same relative lowering of vapour pressure, assuming ‘x’ to ba a non-electrolyte, the molecular weight of ‘x’ is

The correct option is C 60w1M1=w2M26180=2M2M2=60

A $6 %$ glucose solution and $2 %$ solution of ‘x’ show same relative lowering of vapour pressure, assuming ‘x’ to ba a non-electrolyte, the molecular weight of ‘x’ is

The correct option is C 60
$\frac{w_{1}}{M_{1}} = \frac{w_{2}}{M_{2}} \frac{6}{180} = \frac{2}{M_{2}} M_{2} = 60$