A $6 k g$ mass moving with a velocity of $20 m s^{- 1}$ collides with another $2 k g$ mass moving in opposite direction with a velocity of $10 m s^{- 1}$ . The momentum of system is.

140 k g m s^{- 1}

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50 k g m s^{- 1}

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100 k g m s^{- 1}

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Solution

The correct option is C $100 k g m s^{- 1}$
Let: $m_{1} = 6 k g$ , $m_{2} = 2 k g$ , : $u_{1} = 20 m s^{- 1}$ , $u_{2} = - 10 m s^{- 1}$ (negative sign indicates that body is moving in oppostie direction)
$∴$ Momentum of system:
$m_{1} u_{1} + m_{2} u_{2} = (6) (20) - (2) (10)$
$\Rightarrow 100 k g m s^{- 1}$

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A 6 kg mass moving with a velocity of 20 ms−1 collides with another 2 kg mass moving in opposite direction with a velocity of 10 ms−1. The momentum of system is.

The correct option is C 100 kg ms−1Let: m1=6 kg, m2=2 kg, : u1=20 ms−1, u2=−10 ms−1(negative sign indicates that body is moving in oppostie direction) ∴ Momentum of system: m1u1+m2u2=(6)(20)−(2)(10) ⇒100 kg ms−1

A $6 k g$ mass moving with a velocity of $20 m s^{- 1}$ collides with another $2 k g$ mass moving in opposite direction with a velocity of $10 m s^{- 1}$ . The momentum of system is.