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Center of Mass as an Average Point

Question:A 6 ...

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A 6-kg weight is fastened to the end of a steel wire of unstreched length 60 cm. It is whirled in a vertical circle and has an angular velocity of 2 revolution per second at the bottom of the circle. The area of cross-section of the wire is 0.05cm2. The elongation of the wire when the weight is at the lowest point of the path is (Ysteel=2×1011Pa)

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A 6-kg weight is fastened to the end of a steel wire of unstreched length 60 cm. It is whirled in a vertical circle and has an angular velocity of 2 revolution per second at the bottom of the circle. The area of cross-section of the wire is $0.05 c m^{2}$ . The elongation of the wire when the weight is at the lowest point of the path is $(Y_{s t e e l} = 2 \times 10^{11} P a)$

A 6-kg weight is fastened to the end of a steel wire of unstreched length 60 cm. It is whirled in a vertical circle and has an angular velocity of 2 revolution per second at the bottom of the circle. The area of cross-section of the wire is $0.05 c m^{2}$ . The elongation of the wire when the weight is at the lowest point of the path is $(Y_{s t e e l} = 2 \times 10^{11} P a)$

6

-kg weight is fastened to the end of a steel wire of un-stretched length

60

cm. It is whirled in a vertical circle and has an angular velocity of

2

revolution per second at the bottom of the circle. The area of cross-section of the wire is

0.05 c m^{2}

. Calculate the elongation of the wire when the weight is at the lowest point of the path. Young's modulus of steel

= 2 \times 10^{11}

Q. A 6-kg weight is fastened to the end of a steel wire of un-stretched length 60 cm. It is whirled in a vertical circle and has an angular velocity of 2 revolutions per second at the bottom of the circle. The area of cross-section of the wire is

0.05 c m^{2}

. Calculate the elongation of the wire when the weight is at the lowest point of the path. Young's modulus of steel =

2 \times 10^{11}

Q. A 6 kg weight is fastened to the end of a steel wire of unstretched length 60 cm. It is whirled in a vertical~~ circle and has an angular velocity of 2 rev/s at the bottom of the circle. The area of cross-section of the. i wire is

0.05 c m^{2}

. Calculate the elongation of the wire when the weight is at the lowest point of the path . Young's modulus of steel

= 2 \times 10^{11}

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