Question

A 6Ω resistance wire is doubled up by folding. Calculate the new resistance of the wire.

Answer 1

$$\begin{gathered} DearStudent, \\ Weknow, \\ R=\rho \frac{l}{A} \\ Itisgiven. \\ 6=\rho \frac{l}{A}.............\left(1\right) \\ Now, \\ l\to \frac{l}{2}andA\to 2A(Asthewireisfolded) \\ Newresis\tan ceis, \\ {R}^{\text{'}}=\rho \frac{{\displaystyle \frac{l}{2}}}{2A}=\rho \frac{l}{4A}=\frac{1}{4}\times \rho \frac{l}{A}=\frac{1}{4}\times 6=1.5\Omega (from1) \\ Regards.... \end{gathered}$$