A 60kg body is pushed with just enough force to start it moving across a floor and the same force continues to act afterwards. The coefficient of static friction and sliding friction are 0.5 and 0.4 respectively. The acceleration of the body is
A
6m/s2
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B
3.92m/s2
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C
1m/s2
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D
4.9m/s2
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Solution
The correct option is C1m/s2 Formula Used: f=μN
Given: m=60kg,μs=0.5,μk=0.4,
Limiting friction=μs=0.5(60g)=300N
Kinetic friction=μk=0.4(60g)=240N
Formula Used: a=Fnetm ∵F=300N
As force is applied just to balance static friction and once block started moving applied force remained the same and kinetic friction started acting on it
Hence, acceleration a=(300−240)60=1m/s2