A 60 kg body is pushed with just enough force to start it moving across a floor and the same force continues to act afterwards. The coefficient of static friction and sliding friction are 0.5 and 0.4 respectively. The acceleration of the body is
A
9.8m/s2
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B
3.2m/s2
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C
1m/s2
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D
5m/s2
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Solution
The correct option is B1m/s2 The Uniting friction =μsR μsmg=0.5×60×10=300N Kinetic friction =μkR=μkmg =0.4×60×10=240N Force applied = 300 N Net accelerating force = Applied force - kinetic friction ⇒ ma = 300 - 240 = 60 ⇒a=6060=1m/s2