A $60 k g$ man moved $25$ steps up in $25 s$ . Find the power if each step is $16 c m$ high. Take the value of $g = 10 m s^{- 2}$ .

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Solution

Step 1: Data provided,
$M a s s (m) = 60 k g T i m e (t) = 25 s N u m b e r o f s t e p s = 25 H e i g h t o f e a c h s t e p = 16 c m$
Step 2: Formula used and Calculation:
$W o r k d o n e (W) = m g h P o w e r (P) = \frac{W o r k d o n e}{t i m e}$
$T o t a l h e i g h t (h) = N u m b e r o f s t e p s \times h e i g h t o f e a c h s t e p h = 25 \times 16 c m = 400 c m = 4 m W o r k d o n e (W) = m g h W = 60 k g \times 10 m s^{- 2} \times 4 m = 2400 J P o w e r (P) = \frac{W o r k d o n e}{t i m e} P = \frac{2400 J}{25 s} = 96 W$
Hence, the required power is 96 W.

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