A 60kg mass is pushed with a enough force to start it moving and the same force is continued to act afterward. If the coefficient of static friction and sliding friction are 0.5 and 0.4 respectively, then the acceleration of the body will be
A
1ms−2
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B
3.9ms−2
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C
4.9ms−2
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D
6ms−2
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Solution
The correct option is A1ms−2 Kinetic friction =μkR=μkmg=0.4×60×10=240N and the limiting friction =μSR=μSmg=0.5×60×10=300N So, the force applied on the body is 300N and if the body is moving afterwards with the same force, then Net accelerating force = Applied force − Kinetic force ma=300−240 a=60m=6060=1ms−2.