Question

A 60 $\mu$F capacitor is connected to a 110 V (rms), 60Hz ac supply. The rms value of Current in the circuit is:

• A. 1.49 A
• B. 14.9 A
• C. 2.49 A
• D. 24.9 A

Answer 1

Answer: (C)

2.49 A

Capacitor $C=60\mu F$

Peak voltage $V_{rms}=110V$

AC supply freqency $f=60Hz$

$I_{rms}=\frac{V_{rms}}{X_C}$

Capacitive Reactance $X_C=\frac{1}{wC}$

$I_{rms}=\frac{V_{rms}}{\frac{1}{wC}}$

$\therefore I_{rms}=V_{rms}2\pi fC$

$\therefore I_{rms}=110\times 2\pi \times 60\times 60\times {10}^{-6}$

$\therefore I_{rms}=2.49A$

Thus the rms value of current in the circuit is $2.49A$