Question

A $600W$ carrier is modulated to a depth of $75\%$ by a $400Hz$ sine wave. The total antenna power is

• A. $769W$
• B. $796W$
• C. $679W$
• D. $637.5W$

Answer 1

The correct option is A $769W$

$P_{tot}=P_{carrier}(1+\frac{m^2}{2})$

$=600(1+\frac{{0.75}^2}{2})=768.75KW$.