Question

A $68$ boxes of a certain community requires a self length $13.6m$. How many boxes of the same community occupy the self of $20.4m$.

Answer 1

According to the question,

A certain community requires a self length $13.6m$ $=68boxes$

A certain community requires a self length $1m$ $=\frac{68}{13.6}=5boxes$

Therefore,

A certain community requires a self length $20.4m$ $=5\times 20.4=102boxes$

Hence, this is the answer.