A $680 k g$ rocket is to be lifted off on the surface of the moon, where $g = 1.67$ meters per second squared. What force is required to give an upward acceleration of $2.0$ meters per second squared

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Solution

From equation of motion
$F - m g = m a$

$F - 680 (1.67) = 680 (2)$

$F = 2496 N$ .

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A 680 kg rocket is to be lifted off on the surface of the moon, where g=1.67 meters per second squared. What force is required to give an upward acceleration of 2.0 meters per second squared

From equation of motionF−mg=maF−680(1.67)=680(2)F=2496N.

A $680 k g$ rocket is to be lifted off on the surface of the moon, where $g = 1.67$ meters per second squared. What force is required to give an upward acceleration of $2.0$ meters per second squared

From equation of motion
$F - m g = m a$

$F - 680 (1.67) = 680 (2)$

$F = 2496 N$ .