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Question

A 68nm length double stranded DNA has 24 adenine nucleotices. What must be the number of guanine nucleotides?

A
48
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B
72
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C
76
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D
176
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Solution

The correct option is D 176
Length of 3.4nm includes 10 base pairs.So, 68nm will include 200 base pairs that is 400 bases.
A=T AND G=C,
A+T+G+C=400,
24+24+2G=400.,
2G = 352.
So, Guanine nucleotides would be 176.
Hence, the correct answer is option D.

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