Question

A $68nm$ length double stranded DNA has 24 adenine nucleotices. What must be the number of guanine nucleotides?

• A. $48$
• B. $72$
• C. $76$
• D. $176$

Answer 1

The correct option is D $176$

Length of $3.4nm$ includes $10$ base pairs.So, $68nm$ will include $200$ base pairs that is $400$ bases.

A=T AND G=C,

A+T+G+C=$400$,

$24$+$24$+$2G$=$400$.,

$2G$ = $352$.

So, Guanine nucleotides would be $176$.

Hence, the correct answer is option D.