A = (7, -2) and C = (-1, -6) are the vertices of square ABCD. Find the equations of diagonals AC and BD.
We know that in a square, diagonals bisect each other at right angle.
Let O be the point of intersection of the diagonals AC and BD.
Co-ordinates of O are
Slope of AC =
For line AC:
Slope = m = , (x1, y1) = (7, -2)
Equation of the line AC is
y - y1 = m(x - x1)
y + 2 = (x - 7)
2y + 4 = x - 7
2y = x - 11
For line BD:
Slope = m = , (x1, y1) = (3, -4)
Equation of the line BD is
y - y1 = m(x - x1)
y + 4 = -2(x - 3)
y + 4 = -2x + 6
2x + y = 2