Question

A $7.5$ wide two-lane road on a plain terrain is to be laid along a horizontal curve of radius $500m$. For a design speed of $100kmph$, super elevation is provided as per $IRC:73-1980$. Consider acceleration due to gravity as $9.81m/s^2$. The level difference between the inner and outer edges of the road will be

• A. $0.52m$
• B. $0.66m$
• C. $0.62m$
• D. $0.58m$

Answer 1

The correct option is A $0.52m$

$\because e=\frac{V^2}{225R}$

$\therefore e=\frac{{100}^2}{225\times 500}=0.088>0.07$

So,
$e=0.07$
$\Delta h=eB=0.07\times 7.5=0.525m$