A 70 L mixture of juice and water contains 10% of water. How much water must be added to make the water content 12.5% of the resulting mixture?

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Solution

Let the required quantity of water = $x$ L

According to the question,
$70 \times \frac{10}{100} + x = (70 + x) \times \frac{12.5}{100}$

$\Rightarrow 7 + x = (70 + x) \times 0.125$
$\Rightarrow 7 + x = 8.75 + 0.125 x$
$\Rightarrow x - 0.125 x = 8.75 - 7$
$\Rightarrow 0.875 x = 1.75$
$\Rightarrow x = 2$

2 L of water must be added to make the mixture contain 12.5% of water.

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A 70 L mixture of juice and water contains 10% of water. How much water must be added to make the water content 12.5% of the resulting mixture?

Let the required quantity of water = x L According to the question, 70×10100+x=(70+x)×12.5100 ⇒7+x=(70+x)×0.125 ⇒7+x=8.75+0.125x ⇒x−0.125x=8.75−7 ⇒0.875x=1.75 ⇒x=2 2 L of water must be added to make the mixture contain 12.5% of water.