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Question

A 70% solution (solution 1) of H2SO4 is mixed with a 40% solution (solution 2) of the acid to obtain a 60% solution (solution 3). If solution 1 and solution 2 are mixed in a ratio (by mass) of x:1, the value of x is  


Solution

Let x g of 70% H2SO4 be mixed with y g of 40% H2SO4 to obtain (x+y) g 60% H2SO4.
So, x×0.7+y×0.4x+y×100=60
xy=0.20.1=21

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