A 700 g solid cube having an edge of length 10 cm float in water. How much volume of the cube is outside the water? (Density of water = 1000 kg $m^{- 3}$ )

$100 c m^{3}$

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$300 c m^{3}$

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$700 c m^{3}$

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$400 c m^{3}$

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Solution

The correct option is B
$300 c m^{3}$

Weight of cube is balanced by buoyant force

$c ρ g = (0.7 \times g)$

$v = \frac{0.7}{1000} = 7 \times 10^{- 4} m^{3} = 700 c m^{3}$

Volume outside the water is $= 1000 - 700 = 300 c m^{3}$

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700 g

10 c m

1000 k g m^{- 3}

700 g m

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2 m^{3}

ρ_{w a t e r} = 1000 k g m^{- 3}

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