A 700 N man stands on a scale on the floor of an elevator. The scale records the force it exerts on whatever is on it. If the reading is 840N in the scale then the elevator has an accelerations of (g= $10 m {/ s}^{2}$ )

2 m {/ s}^{2} u p

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1.8 m {/ s}^{2} d o w n

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10 m {/ s}^{2} d o w n

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None of these

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Solution

The correct option is A $2 m {/ s}^{2} u p$
Actual mass of the man will be $m = \frac{W e i g h t}{g} = \frac{700 N}{10 m / s^{2}} = 70 K g$
When the elevator will go $u p w a r d$ the $p s u e d o$ force on the man
will be $d o w n w a r d$ and the weigh also being downward, $c o n s e q u e n t l y$ both will be get added and the reading will be
$m g + p s u e d o = 700 N + 70 \times a$
as the reading is given as $840 N$ so $840 = 700 + 70 a$
or $a = 2 m / s^{2}$ upward

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A 700 N man stands on a scale on the floor of an elevator. The scale records the force it exerts on whatever is on it. If the reading is 840N in the scale then the elevator has an accelerations of (g= 10m/s2)

A 700 N man stands on a scale on the floor of an elevator. The scale records the force it exerts on whatever is on it. If the reading is 840N in the scale then the elevator has an accelerations of (g= $10 m {/ s}^{2}$ )