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Question

A 700 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water? Density of water =1 g/cm3.

A
700 cm3
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B
300 cm3
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C
1000 cm3
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D
30 cm3
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Solution

The correct option is B 300 cm3
The weight of the cube is balanced by the buoyant force. The buoyant force is equal to the weight of the water displaced. If V volume of the cube is inside the water, the weight of the displaced water =Vρ g, where ρ is the density of water. Thus,
Vρg=mg

Vρg=700×g
V=700ρ=700 cm3
The total volume of the cube =(10 cm)3=1000 cm3.
The volume of cube outside the water is 1000 cm3700 cm3=300 cm3


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