A $750 W$ motor drives a pump which lifts $300$ litres of water per minute to a height of $6$ meters. The efficiency of the motors is nearly (take acceleration due to gravity to be $10 m / s^{2}$ )

30 %

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40 %

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50 %

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20 %

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Solution

The correct option is B $40 %$
$η = \frac{m g h / t}{750} \times 100$
$= \frac{\frac{300 \times 10 \times 6}{60}}{750} \times 100$ $= \frac{300}{750} \times 100$
$= 40 %$

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A 750W motor drives a pump which lifts 300 litres of water per minute to a height of 6 meters. The efficiency of the motors is nearly (take acceleration due to gravity to be 10m/s2 )

The correct option is B 40%η=mgh/t750×100=300×10×660750×100 =300750×100 =40%

A $750 W$ motor drives a pump which lifts $300$ litres of water per minute to a height of $6$ meters. The efficiency of the motors is nearly (take acceleration due to gravity to be $10 m / s^{2}$ )

The correct option is B $40 %$
$η = \frac{m g h / t}{750} \times 100$
$= \frac{\frac{300 \times 10 \times 6}{60}}{750} \times 100$ $= \frac{300}{750} \times 100$
$= 40 %$