You visited us 1 times! Enjoying our articles? Unlock Full Access!

Redox Reactions

A 8 gm sample...

Question

A $8 g m$ sample of iron are containing $V %$ (by wt) of iron $F e^{2 +}$ was present in $1 L$ solution. This solution required $V m L$ of a $K M n O_{4}$ solution for oxidation of $F e^{2 +}$ in acidic medium. If in another titration $20 m L$ of same $K M n O_{4}$ is required, for oxidation of $20 m L H_{2} O_{2}$ in acidic medium. Find volume strength of $H_{2} O_{2}$

Open in App

Solution

$M e q . o f F e^{2 +} = m e q . o f K M n O_{4} = \frac{8 \times V \times 1 \times 1000}{100 \times 56} = N_{K M n O_{4}} \times V$
$N = \frac{8}{5.6}$
As equivalent weight of $K M n O_{4}$ is same in both the experiment so , $N_{K M n O_{4}}$ is same in both.
$M e q o f K M n O_{4} = m e q . o f H_{2} O_{2}$
$20 \times \frac{8}{5.6} = 20 \times N = 20 \times \frac{V o l . s t r e n g t h}{5.6}$
So, volume strength of $H_{2} O_{2} = 8$

Suggest Corrections

Similar questions

8 g m

V %

F e^{2 +}

1 L

V m L

K M n O_{4}

F e^{2 +}

20 m L

K M n O_{4}

20 m L H_{2} O_{2}

H_{2} O_{2}

K M n O_{4}

H_{2} O_{2}

K M n O_{4}

H_{2} O_{2}

1

H_{2} O_{2}

x

H_{2} O_{2}

x

K M n O_{4}

K M n O_{4}

H_{2} O_{2}

K M n O_{4}

H_{2} O_{2}

g

H_{2} O_{2}

x

K M n O_{4}

K M n O_{4}

Join BYJU'S Learning Program