Question

A $900kg$ car moving at $10m/s$ takes a turn around a circular path of radius $25m$. The centripetal acceleration and the centripetal force acting on the car is given by (Neglect friction between all surfaces)

• A. $2m/s^2;3600N$
• B. $4m/s^2,3600N$
• C. $2m/s^2,1800N$
• D. $4m/s^2,1800N$

Answer 1

The correct option is B $4m/s^2,3600N$

Given $m=900kg$, $v=10m/s$, $r=25m$

Centripetal acceleration of car,
$a_c=\frac{v^2}{r}=\frac{(10{)}^2}{25}=4m/s^2$

$\therefore$$F_{centripetal}=m\times a_c$
$=900\times 4=3600N$