A A point P divides the line segment joining the points A 3-5 and B -4-8 such that AP - BP - k -1- If P lies on the line x - y -0-then find the value of kb- The volume of a hemisphere is 2425 1-2 cm 3- Find its CSA

A) a=b( 4)+1(3)/b+1 y=b(8)+1( 5)/b+1 = 4b+3/b+1 = 8b 5/b+1 (x,y) lies of x+y=0 ⇒ 4b+3/b+1+8b 5/b+1=0 ⇒ 4b+3+8b 5/b+1=0 ⇒4b 2/b+1=0 ⇒ 4b 2=0 b=2/4=1/ ...

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a A point P d...

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(a) A point P divides the line segment joining the points $A (3, - 5)$ and $B (- 4, 8)$ such that $\frac{A P}{B P} = \frac{k}{1}$ . If P lies on the line x+y=0 ,then find the value of k

(b). The volume of a hemisphere is 2425 $\frac{1}{2} c m^{3}$ . Find its CSA

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Solution

a)

$a = \frac{b (- 4) + 1 (3)}{b + 1} y = \frac{b (8) + 1 (- 5)}{b + 1}$
$= - \frac{4 b + 3}{b + 1}$ $= \frac{8 b - 5}{b + 1}$
$(x, y) l i e s o f x + y = 0$
$\Rightarrow \frac{- 4 b + 3}{b + 1} + \frac{8 b - 5}{b + 1} = 0 \Rightarrow \frac{- 4 b + 3 + 8 b - 5}{b + 1} = 0 \Rightarrow \frac{4 b - 2}{b + 1} = 0 \Rightarrow 4 b - 2 = 0 b = \frac{2}{4} = \frac{1}{2}$

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Q. A point

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A point P divides the line segment joining the points $A (3, - 5)$ and $B (- 4, 8)$ such that $\frac{A P}{B P} = \frac{K}{1}$ . If P lies on the line $x + y = 0,$ then fine the value of K.

Q. A point P divides the line segment joining the points A(3, −5) and B(−4, 8) such that

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If P lies on the line x + y = 0, then find the value of k. [CBSE 2012]

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(a) A point P divides the line segment joining the points A(3,−5) and B(−4,8) such that APBP=k1 . If P lies on the line x+y=0 ,then find the value of k (b). The volume of a hemisphere is 2425 12cm3. Find its CSA

a) a=b(−4)+1(3)b+1y=b(8)+1(−5)b+1 =−4b+3b+1 =8b−5b+1 (x,y) lies of x+y=0 ⇒−4b+3b+1+8b−5b+1=0⇒−4b+3+8b−5b+1=0⇒4b−2b+1=0⇒4b−2=0 b=24=12

(a) A point P divides the line segment joining the points $A (3, - 5)$ and $B (- 4, 8)$ such that $\frac{A P}{B P} = \frac{k}{1}$ . If P lies on the line x+y=0 ,then find the value of k

(b). The volume of a hemisphere is 2425 $\frac{1}{2} c m^{3}$ . Find its CSA