A)A suitcase with measure 40cm×24cm×12cm is to be covered with a tarpaulin of width 48cm is required to cover such 10 suitcases?
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Solution
The suitcase l = 40 cm b = 24 cm h = 12 cm therefore, Total Surface Area = 2(lb + bh + lh) = 2 [(40*24) + (24*12) + (40*12)] = 2 (960 + 288 +480 ) = 2 * 1728 = 3456 cm^2
Length of cloth required = (area of suitcase/ breadth) * 100 = (3456/ 48) * 100 = 72 * 100 = 7200 cm = 7200 /100 m = 72 m