A and B are 2 stations 390 km apart. A train start from A at 10am and travels towards B at 65kmph. Another train start from B at 11am and travels towards A at 35kmph. At what time do they meet.

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Solution

Till $11$ am train $A$ covers distance of $65$ cm. So remaining distance $(390 - 65) = 325$ km.
Relative speed $= 100$ km/hr
So to cover $100$ km $= 1$ hr.
Therefore to cover $325$ km in $x h r$
$x = \frac{325}{100} h r s = 3.25$ hrs
Hence the train meet at $11$ am $+ 3.25$ hrs $= 2.25$ pm.

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A and B are 2 stations 390 km apart. A train start from A at 10am and travels towards B at 65kmph. Another train start from B at 11am and travels towards A at 35kmph. At what time do they meet.

Till 11 am train A covers distance of 65 cm. So remaining distance (390−65)=325 km.Relative speed =100 km/hrSo to cover 100 km =1 hr.Therefore to cover 325 km in xhrx=325100hrs=3.25 hrsHence the train meet at 11 am +3.25 hrs =2.25 pm.

Till $11$ am train $A$ covers distance of $65$ cm. So remaining distance $(390 - 65) = 325$ km.
Relative speed $= 100$ km/hr
So to cover $100$ km $= 1$ hr.
Therefore to cover $325$ km in $x h r$
$x = \frac{325}{100} h r s = 3.25$ hrs
Hence the train meet at $11$ am $+ 3.25$ hrs $= 2.25$ pm.