$A$ and $B$ are events such that $P (A) = 0.42, P (B) = 0.48$ and P(A and B) $= 0.16$
Determine (i) P(not A), (ii) P(not B) and (iii) P(A or B)

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Solution

It is given that $P (A) = 0.42, P (B) = 0.48, P (A and B) = 0.16$
(i) $P (not A) = 1 - P (A) = 1 - 0.42 = 0.58$
(ii) $P (not B) = 1 - P (B) = 1 - 0.48 = 0.52$
(iii) We know that $P (A o r B) = P (A) + P (B) - P (A and B)$
$∴ P (A o r B) = 0.42 + 0.48 - 0.16 = 0.74$

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Similar questions

A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (i) P(not A), (ii) P (not B) and (iii) P(A or B).

A and B are events such that P(A) = 0.42,
P(B) = 0.48 and P(A and B) = 0.16. Determine
(i) P (not A ) (ii) P (not B) and (iii) P (A or B)

A and B are two events such that P(A) = 0.54, P(B) = 0.69 and P(A \cap B) = 0.35.
Find
(i) $P (A \cap B)$ (ii) P $(A^{'} \cap B^{'})$ (iii) P $(A \cap B^{'})$
(iv) P $(A \cap B^{'})$

Q. A and B are two events such that P(A) = 0.54, P(B) = 0.69 and P(A ∩ B) = 0.35. Find (i) P(A ∩ B) (ii) P(A′ ∩ B′) (iii) P(A ∩ B′) (iv) P(B ∩ A′)

A

and

B

are two events such that

P (A) = 0.54, P (B) = 0.69

and P(A

\cap

= 0.35

Find (i) P(A

\cup

B)
(ii) P(A'

\cap

B')
(iii) P(A

\cap

B')
(iv) P(B

\cap

A')

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A and B are events such that P(A)=0.42,P(B)=0.48 and P(A and B) =0.16Determine (i) P(not A), (ii) P(not B) and (iii) P(A or B)

It is given that P(A)=0.42,P(B)=0.48,P(AandB)=0.16(i) P(notA)=1−P(A)=1−0.42=0.58(ii) P(notB)=1−P(B)=1−0.48=0.52(iii) We know that P(AorB)=P(A)+P(B)−P(AandB)∴P(AorB)=0.42+0.48−0.16=0.74

$A$ and $B$ are events such that $P (A) = 0.42, P (B) = 0.48$ and P(A and B) $= 0.16$
Determine (i) P(not A), (ii) P(not B) and (iii) P(A or B)

It is given that $P (A) = 0.42, P (B) = 0.48, P (A and B) = 0.16$
(i) $P (not A) = 1 - P (A) = 1 - 0.42 = 0.58$
(ii) $P (not B) = 1 - P (B) = 1 - 0.48 = 0.52$
(iii) We know that $P (A o r B) = P (A) + P (B) - P (A and B)$
$∴ P (A o r B) = 0.42 + 0.48 - 0.16 = 0.74$