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Question

A and B are friends. Ignoring the leap year, find the probability that both friends will have different birthdays is m365.Find m

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Solution

An year has 365 days.
So, total number of possibilities = 365*365
But, it is given that they should have different birthdays. So, Number of ways = 3652P
Probability = 3652P(365)2
=364365

m=364


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