A and B are sections of two long parallel wires placed perpendicular to the plane of the paper. They carry current of $5 A$ and $10 A$ respectively in the directions indicated in the figure. If the separation between them is $3 m$ , the zero of the magnetic field in the plane of the paper is at a point :

3 m

to the left of A

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3 m

to the right of B

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2 m

to the right of A

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2 m

to the left of B

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Solution

The correct option is D $2 m$ to the left of B
Let magnetic field be at a point x from A.
= $\frac{μ_{o} i_{a}}{2 A x} = \frac{μ_{o} i_{b}}{2 A (r - x)}$
= $\frac{5}{x} = \frac{10}{3 - x}$
$3 - x = 2 x$
$⟹ x = 1 m$
$∴$ distance from B is $2 m$ to the left.

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A and B are sections of two long parallel wires placed perpendicular to the plane of the paper. They carry current of 5A and 10A respectively in the directions indicated in the figure. If the separation between them is 3m, the zero of the magnetic field in the plane of the paper is at a point :

The correct option is D 2m to the left of BLet magnetic field be at a point x from A.= μoia2Ax=μoib2A(r−x)= 5x=103−x3−x=2x ⟹x=1m∴ distance from B is 2m to the left.

The correct option is D $2 m$ to the left of B
Let magnetic field be at a point x from A.
= $\frac{μ_{o} i_{a}}{2 A x} = \frac{μ_{o} i_{b}}{2 A (r - x)}$
= $\frac{5}{x} = \frac{10}{3 - x}$
$3 - x = 2 x$
$⟹ x = 1 m$
$∴$ distance from B is $2 m$ to the left.