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Question

A and B are seeking admission into IIT. If the probability for A to be selected is 0.5 and that both to be selected is 0.3, them is it possible that, the probability of B to be selected is 0.9?

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Solution

Given that probability of A is P(A)=0.5

and probability that both A and B to be selected is P(AB)=0.3

We know that P(AB)=P(A)+P(B)P(AB)

1=0.5+P(B)0.3

1=0.2+P(B)

P(B)=0.8

Therefore, P(B) cannot be 0.9

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