Question

A and B are two alloys of gold and copper prepared by mixing metals in the ratio of 5:3 and 5:11 respectively. Equal quantities of these alloys are melted to form a third alloy C. The ratio of gold and copper in alloy C is:

• A. 25:13
• B. 33:15
• C. 15:17
• D. 17:15

Answer 1

The correct option is C 15:17

Total quantities of Alloy $A=5+3=8$

Total quantity of Alloy $B=5+11=16$

LCM of $8$ and $16$ is $16$.

Then we have quantity of A in C as $(10+6)$

We have quantity of A and B as $(5+11)$

Hence the ratio is $(10+5):(6+11)⟹15:17$.